List of funerals at milton keynes crematorium, Nov 2, 2010 · When reading, list is a reference to the original list, and list[:] shallow-copies the list. If your list of lists comes from a nested list comprehension, the problem can be solved more simply/directly by fixing the comprehension; please see How can I get a flat result from a list comprehension instead of a nested list?. When assigning, list (re)binds the name and list[:] slice-assigns, replacing what was previously in the list. Why is the output of the following two list comprehensions different, even though f and the lambda function are the same? Oct 5, 2012 · By using a : colon in the list index, you are asking for a slice, which is always another list. Other than that I think the only difference is speed: it looks like it's a little faster the first way. Also, don't use list as a name since it shadows the built-in. Since the code in test works for any kind of object in the list, this works as a formal method parameter. Try it yourself with timeit. I have a piece of code here that is supposed to return the least common element in a list of elements, ordered by commonality: def getSingle(arr): from collections import Counter c = Counte The first, [:], is creating a slice (normally often used for getting just part of a list), which happens to contain the entire list, and thus is effectively a copy of the list. : represents going through the list -1 implies the last element of the list Official Google Search Help Center where you can find tips and tutorials on using Google Search and other answers to frequently asked questions.
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